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English Version

题目描述

给你一个字符串 s ,将该字符串中的大写字母转换成相同的小写字母,返回新的字符串。

 

示例 1:

输入:s = "Hello"
输出:"hello"

示例 2:

输入:s = "here"
输出:"here"

示例 3:

输入:s = "LOVELY"
输出:"lovely"

 

提示:

  • 1 <= s.length <= 100
  • s 由 ASCII 字符集中的可打印字符组成

解法

遍历字符串,遇到大写的字符,转小写。

Python3

class Solution:
    def toLowerCase(self, s: str) -> str:
        return ''.join(
            [chr(ord(c) | 32) if ord('A') <= ord(c) <= ord('Z') else c for c in s]
        )

Java

class Solution {
    public String toLowerCase(String s) {
        char[] chars = s.toCharArray();
        for (int i = 0; i < chars.length; ++i) {
            if (chars[i] >= 'A' && chars[i] <= 'Z') {
                chars[i] |= 32;
            }
        }
        return new String(chars);
    }
}

C++

class Solution {
public:
    string toLowerCase(string s) {
        for (char& c : s)
            if (c >= 'A' && c <= 'Z')
                c |= 32;
        return s;
    }
};

Go

func toLowerCase(s string) string {
	sb := &strings.Builder{}
	sb.Grow(len(s))
	for _, c := range s {
		if c >= 'A' && c <= 'Z' {
			c |= 32
		}
		sb.WriteRune(c)
	}
	return sb.String()
}

Rust

impl Solution {
    pub fn to_lower_case(s: String) -> String {
        s.to_ascii_lowercase()
    }
}
impl Solution {
    pub fn to_lower_case(s: String) -> String {
        String::from_utf8(
            s.as_bytes()
                .iter()
                .map(|&c| c + if c >= b'A' && c <= b'Z' { 32 } else { 0 })
                .collect(),
        )
        .unwrap()
    }
}

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