is_wise_enum_class and is_wise_enum_vanilla?

[sahilsharma-github]

I am using wise_enum library and i have a requirement to distinguish if something is an enum class or plain vanilla enum at compile time. wise enum provides a way to check if something is a wise_enum, which also implicitly means that it can tell us if something is an enumeration type. This is because wise_enum creates an actual scoped or unscoped class.

I looked into C++ standard to check if there is an existing type-trait that distinguishes between enum class and vanilla enum.
i found :
std::is_enum // again does not distinguish between scoped and unscoped enums
std::is_scoped_enum // exactly what i need, but unfortunately it's proposed for C++23

I think i am going to end up implementing this on my own. But i think it adds value to wise_enum also if it has this kind of type introspection available as C++23 is still a few years i think.

I am happy to add this enhancement to WISE_ENUM as well.

Interested in some feedback here!

Cheers